11-03-2012, 08:39 PM
Thanks PJW,
So let me see if I have understood this in my own words. I will write it up later to see if I really have got it.
The headway time for a non stopping train following a stopping train can be calculated by adding the difference from the headway time for a stopping train following a stopping train, minus the time a non stopping train would take to cover the same distance.
Ht (ns f s) = Ht (ns) + [Ht(s f s) - time taken for Ht(ns) to cover the same distance]
It looks more understandable on my sketch pad!
And it only appears to add an extra 110 seconds to the headway time, which would fit in with the question requirements. Making 3mins 10secs headway time.
Regards
KJB
So let me see if I have understood this in my own words. I will write it up later to see if I really have got it.
The headway time for a non stopping train following a stopping train can be calculated by adding the difference from the headway time for a stopping train following a stopping train, minus the time a non stopping train would take to cover the same distance.
Ht (ns f s) = Ht (ns) + [Ht(s f s) - time taken for Ht(ns) to cover the same distance]
It looks more understandable on my sketch pad!
And it only appears to add an extra 110 seconds to the headway time, which would fit in with the question requirements. Making 3mins 10secs headway time.
Regards
KJB